Types

type FuncType func()

It is possible to add method a to func type?!

func (f FuncType) callFn() {
	f()
}

type IntType int

type anyStruct struct {
	param any
}

Add method to int type

func (i IntType) getInt() {
	fmt.Println("selected type: ", i)
}

Methods on types

var fnType FuncType
fnType = func() {
	fmt.Println("inside FuncType")
}
// More advance example a function type call a method of that method
fnType.callFn()

method on int

var intType IntType
intType = 1
intType.getInt()

Int types

there is some types for int and float
basically int: int, int8, int16, int32, int64
go get type by inference and set int, that is based on processor architecture
go get type by inference and set int, that is based on processor architecture

num := 1
fmt.Println("infer int type: ", reflect.TypeOf(num))

It is not possible to make operations with differents types like int8 + int1
var byt int8 = 1
var byt2 int16 = 2
X Error

byt+byt2   

X error:

var variable uint = -1   

rune is alias for int32
byte is an alias for uint8

returns int

fmt.Println(reflect.TypeOf(num))

Other types

for float there is just
float32 and float64

num2 := 2.0
// returns float64
fmt.Println(reflect.TypeOf(num2))

type boolean

isOk := true
fmt.Println(isOk)

type error

var erro error = errors.New("panic internal error")
fmt.Println(erro)

function type
this is anonymous function

whatIsType := func() {}
fmt.Println(reflect.TypeOf(whatIsType))