Two-Pointers-2 solution

[Simranb10]

No description provided.

[super30admin]

Merging of 2 arrays (MergeArray.java)

Strengths:

• Correctly implements the optimal three-pointer approach from the end
• Clean and readable code structure
• Good variable naming conventions
• Includes complexity analysis comments
• Properly handles edge cases (when one array is exhausted)

Areas for Improvement:

• Consider adding inline comments to explain the merging logic, especially for the two-pointer comparison
• The variable name "mid" could be more descriptive as "writeIdx" or "pos" since it represents the current write position, not the middle
• Could add a brief comment explaining why we start from the end (to avoid overwriting elements we still need)

Overall, this is a solid implementation that matches the reference solution in both approach and efficiency.

VERDICT: PASS

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Search 2D sorted matrix II (SearchMatrix.java)

Strengths:

• Excellent choice of algorithm - the top-right corner approach is the optimal solution for this problem
• Time complexity O(m+n) is better than the reference solution's O(m log n)
• Clean, readable code with descriptive variable names
• Proper boundary checks prevent index out of bounds errors
• Well-placed comments explaining the approach

Areas for improvement:

• Consider adding a null/empty matrix check at the beginning for defensive programming, though the constraints guarantee non-empty matrices
• Could add early return documentation explaining why this approach works

The student demonstrates strong understanding of the problem's properties and chose a superior algorithmic approach compared to the reference solution.

VERDICT: PASS

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Edit and Remove Duplicates in an array (RemoveDuplicates.java)

Strengths:

• Your solution correctly solves the problem with the same approach as the reference solution
• Clean, readable code with descriptive variable names
• Proper time and space complexity achieved
• Good use of comments to document complexity

Areas for Improvement:

• The condition fast != 0 && nums[fast] == nums[fast - 1] works correctly, but you could also initialize count = 1 before the loop starts and simplify the logic to just check nums[fast] == nums[fast - 1] without the fast != 0 check
• Consider adding a brief explanation comment for the algorithm logic to make it easier for others to understand your approach

Overall, this is a solid solution that demonstrates good understanding of the two-pointer technique for in-place array modifications.

VERDICT: PASS