Implement Subarray Sum Equals K, Contiguous Array, Longest Palindrome

[ayushcha2701]

No description provided.

[super30admin]

Subarray Sum Equals K (SubarraySumEqualsK.java)

Strengths:

• Correctly implements the prefix sum + hash map technique
• Clean logic flow that matches the standard solution approach
• Good variable naming makes the code self-documenting
• Properly handles edge cases (starting with map.put(0,1))

Areas for Improvement:

• Minor code formatting inconsistency: HashMap < Integer, Integer > has spaces that don't follow typical Java conventions (should be HashMap<Integer, Integer>)
• Consider adding a brief comment explaining the algorithm approach for better maintainability

The solution is functionally equivalent to the reference solution and demonstrates solid understanding of the problem-solving technique.

VERDICT: PASS

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Contiguous Binary Subarray (ContiguousArray.java)

Strengths:

• Correct implementation of the running sum with HashMap technique
• Good use of early initialization (map.put(0, -1)) to handle edge cases
• Clean and readable code structure
• Proper handling of both 0 and 1 cases in the if-else statement

Areas for Improvement:

• The class should be declared as public class ContiguousArray to be accessible
• Consider wrapping this in a Solution class as per standard LeetCode format
• Add comments to explain the algorithm logic for better maintainability
• Variable name rSum could be more descriptive as runningSum
• Consider adding input validation (empty array check)

The solution is functionally correct and matches the reference solution's approach and complexity.

VERDICT: PASS

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Longest Palindrome in a string (LongestPalindrome.java)

Strengths:

• Correctly implements the greedy algorithm for longest palindrome construction
• Clean and readable code structure
• Good variable naming
• Proper handling of the center character for odd-length palindromes

Areas for Improvement:

• Consider using the return value of set.add() instead of separate contains() and add() calls for slightly better performance
• The set.remove(ss) call is redundant when using the two-step approach, but the logic is still correct

Overall, this is a solid solution that matches the reference approach in both correctness and complexity.

VERDICT: PASS