Create Keith Number in Java

Keith Number in Java

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+##Program
+
+import java.util.*;  
+class KeithNumberExample1  
+{  
+//user-defined function that checks if the given number is Keith or not  
+static boolean isKeith(int x)  
+{  
+//List stores all the digits of the X  
+ArrayList<Integer> terms=new ArrayList<Integer>();  
+//n denotes the number of digits   
+int temp = x, n = 0;   
+//executes until the condition becomes false  
+while (temp > 0)  
+{  
+//determines the last digit of the number and add it to the List      
+terms.add(temp%10);  
+//removes the last digit  
+temp = temp/10;  
+//increments the number of digits (n) by 1  
+n++;  
+}  
+//reverse the List  
+Collections.reverse(terms);  
+int next_term = 0, i = n;  
+//finds next term for the series  
+//loop executes until the condition returns true  
+while (next_term < x)  
+{  
+next_term = 0;  
+//next term is the sum of previous n terms (it depends on number of digits the number has)  
+for (int j=1; j<=n; j++)  
+next_term = next_term + terms.get(i-j);  
+terms.add(next_term);  
+i++;  
+}  
+//when the control comes out of the while loop, there will be two conditions:  
+//either next_term will be equal to x or greater than x  
+//if equal, the given number is Keith, else not  
+return (next_term == x);  
+}  
+//driver code  
+public static void main(String[] args)  
+{  
+//calling the user-defined method inside the if statement and print the result accordingly    
+if (isKeith(19))  
+System.out.println("Yes, the given number is a Keith number.");  
+else  
+System.out.println("No, the given number is not a Keith number.");  
+if(isKeith(742))  
+System.out.println("Yes, the given number is a Keith number.");  
+else  
+System.out.println("No, the given number is not a Keith number.");  
+if(isKeith(4578))  
+System.out.println("Yes, the given number is a Keith number.");  
+else  
+System.out.println("No, the given number is not a Keith number.");  
+}  
+}  
+
+#Output:
+
+Yes, the given number is a Keith number.
+Yes, the given number is a Keith number.
+No, the given number is not a Keith number.