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43 lines (39 loc) · 847 Bytes
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Copy path24.asm
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43 lines (39 loc) · 847 Bytes
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;编写一个程序,显示AL寄存器中的两位十六进制数
CSEG SEGMENT
ASSUME CS: CSEG
START:
MOV AL, 0CEH ;给al赋初值
MOV BL, AL ;将bl作为暂存器
MOV BH, 2 ;循环两次输出16进制位
MOV CX, 4
ROL AL, CL ;交换al的高4位和低4位
AND AL, 0FH ;屏蔽高4位
LOP:
CMP AL, 0 ;判断al是否属于0~9
JB EXIT
CMP AL, 9
JA AF ;大于则跳转到判断是否属于a~f
OR AL, 30H
JMP DISP
AF: ;判断是否属于a~f
CMP AL, 10
JB EXIT
CMP AL, 15
JA EXIT
ADD AL, 37H
JMP DISP
DISP: ;显示十六进制数
MOV DL, AL
MOV AH, 02H
INT 21H
DEC BH ;bh减1
CMP BH, 0
JE EXIT
MOV AL, BL
AND AL, 0FH ;屏蔽高4位
JMP LOP
EXIT:
MOV AH, 4CH
INT 21H
CSEG ENDS
END START