Given a 32-bit signed integer, reverse digits of an integer.
Assume we are dealing with an environment that could only store integers within the 32-bit signed integer range: [−231, 231 − 1]. For the purpose of this problem, assume that your function returns 0 when the reversed integer overflows.
Input: x = 123
Output: 321
Input: x = -123
Output: -321
Input: x = 120
Output: 21
Input: x = 0
Output: 0
- -231 <= x <= 231 - 1
- java
/*
Success Detail:
Runtime: 1 ms, faster than 100.00% of Java online submissions for Reverse Integer.
Memory Usage: 35.9 MB, less than 80.80% of Java online submissions for Reverse Integer.
*/
class Solution {
public int reverse(int x) {
int num = 0;
while (x != 0) {
if ((num == Integer.MAX_VALUE / 10 && x % 10 > 8) || num > Integer.MAX_VALUE / 10) {
return 0;
}
if ((num == Integer.MIN_VALUE / 10 && x % 10 > 7) || num < Integer.MIN_VALUE / 10) {
return 0;
}
num = num * 10 + x % 10;
x /= 10;
}
return num;
}
}