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Copy pathSlidingWindowMaximum.java
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113 lines (99 loc) · 2.73 KB
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import java.util.Objects;
/**
*You are given an array of integers nums, there is a sliding window of size k which is moving from the very left of the array to the very right. You can only see the k numbers in the window. Each time the sliding window moves right by one position.
*
* Return the max sliding window.
*
*
*
* Example 1:
*
* Input: nums = [1,3,-1,-3,5,3,6,7], k = 3
* Output: [3,3,5,5,6,7]
* Explanation:
* Window position Max
* --------------- -----
* [1 3 -1] -3 5 3 6 7 3
* 1 [3 -1 -3] 5 3 6 7 3
* 1 3 [-1 -3 5] 3 6 7 5
* 1 3 -1 [-3 5 3] 6 7 5
* 1 3 -1 -3 [5 3 6] 7 6
* 1 3 -1 -3 5 [3 6 7] 7
* Example 2:
*
* Input: nums = [1], k = 1
* Output: [1]
*
*
* Constraints:
*
* 1 <= nums.length <= 10^5
* -10^4 <= nums[i] <= 10^4
* 1 <= k <= nums.length
*
*/
class Solution {
@Override
public boolean equals(Object o) {
if (this == o) return true;
if (o == null || getClass() != o.getClass()) return false;
Solution solution = (Solution) o;
return Objects.equals(window, solution.window);
}
@Override
public int hashCode() {
return Objects.hash(window);
}
Window window = new Window();
public int[] maxSlidingWindow(int[] nums, int k) {
window.arr.clear();
window.k = k;
int cnt = 0, n = nums.length;
int[] ans = new int[n - k + 1];
for(int i = 0; i < nums.length; i++){
if(window.arr.size() == k){
window.remove(nums[i - k]);
}
window.insert(nums[i]);
int temp = window.getMaxElem();
if(window.arr.size() == k) {
ans[cnt++] = temp;
}
}
return ans;
}
class Window{
List<Integer> arr = new ArrayList();
int k;
public int getMaxElem(){
if(arr.size() == k){
return arr.get(arr.size() - 1);
}
return -100000;
}
public void insert(int a){
int st = 0, en = arr.size() - 1;
while(st <= en){
int mid = (st + en) / 2;
if(arr.get(mid) > a){
en = mid - 1;
}else{
st = mid + 1;
}
}
arr.add(st, a);
}
public void remove(int a){
int st = 0, en = arr.size() - 1;
while(st <= en){
int mid = (st + en) / 2;
if(arr.get(mid) > a){
en = mid - 1;
}else{
st = mid + 1;
}
}
arr.remove(en);
}
}
}