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91 lines (72 loc) · 2.43 KB
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/*
Design and implement a data structure for Least Recently Used (LRU) cache. It should support the following operations: get and put.
get(key) - Get the value (will always be positive) of the key if the key exists in the cache, otherwise return -1.
put(key, value) - Set or insert the value if the key is not already present. When the cache reached its capacity, it should invalidate the least recently used item before inserting a new item.
The cache is initialized with a positive capacity.
Follow up:
Could you do both operations in O(1) time complexity?
Example:
LRUCache cache = new LRUCache( 2 /* capacity */ );
cache.put(1, 1);
cache.put(2, 2);
cache.get(1); // returns 1
cache.put(3, 3); // evicts key 2
cache.get(2); // returns -1 (not found)
cache.put(4, 4); // evicts key 1
cache.get(1); // returns -1 (not found)
cache.get(3); // returns 3
cache.get(4); // returns 4
*/
import java.time.*;
class LRUCache {
class ItemInfo{
int value;
LocalTime time;
ItemInfo(int value,LocalTime time){
this.time=time;
this.value=value;
}
}
HashMap<Integer,ItemInfo> map;
int size;
public LRUCache(int capacity) {
map=new HashMap<Integer,ItemInfo>();
size=capacity;
}
public int get(int key) {
if(map.containsKey(key)){
map.get(key).time=LocalTime.now();
return map.get(key).value;
}
return -1;
}
public void put(int key, int value) {
if(map.containsKey(key)) {
map.get(key).time=LocalTime.now();
map.get(key).value=value;
return;
}
if(map.size()==size){
int toDelete=getMinTime(map);
map.remove(toDelete);
}
map.put(key,new ItemInfo(value,LocalTime.now()));
}
public int getMinTime(HashMap<Integer,ItemInfo> map){
LocalTime min=LocalTime.now();
int min_key=0;
for(Map.Entry<Integer,ItemInfo> entry: map.entrySet()){
if(min.isAfter(entry.getValue().time)){
min=entry.getValue().time;
min_key=entry.getKey();
}
}
return min_key;
}
}
/**
* Your LRUCache object will be instantiated and called as such:
* LRUCache obj = new LRUCache(capacity);
* int param_1 = obj.get(key);
* obj.put(key,value);
*/