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Copy path0053_maximum_subarray.py
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52 lines (47 loc) · 2.11 KB
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# Runtime: 124 ms, faster than 5.45% of Python3 online submissions for Maximum Subarray.
# Memory Usage: 13.6 MB, less than 65.85% of Python3 online submissions for Maximum Subarray.
class Solution:
def maxSubArray(self, nums: List[int]) -> int:
'''Method 1: O(n) time'''
# max_sum = float('-inf')
# min_cum_sum = cum_sum = 0
# for i in range(len(nums)):
# min_cum_sum = min(min_cum_sum, cum_sum)
# cum_sum += nums[i]
# max_sum = max(max_sum, cum_sum - min_cum_sum)
# return max_sum
'''divide-and-conquer O(nlogn) time'''
# def max_sub_array(left, right, s):
# if left == right:
# return s[left]
# mid = (left + right) // 2
# return max(max_sub_array(left, mid, s), max_sub_array(mid + 1, right, s), max_cross_array(left, right, mid, s))
# def max_cross_array(left, right, mid, s):
# cur_sum, left_max_sum = 0, float('-inf')
# for i in range(mid, left - 1, -1):
# cur_sum += s[i]
# if cur_sum > left_max_sum:
# left_max_sum = cur_sum
# cur_sum, right_max_sum = 0, float('-inf')
# for i in range(mid + 1, right + 1):
# cur_sum += s[i]
# if cur_sum > right_max_sum:
# right_max_sum = cur_sum
# return left_max_sum + right_max_sum
# return max_sub_array(0, len(nums) - 1, nums)
'''Sol. 1: Optimized brute force, time O(n^2) space O(1)'''
# max_ans = nums[0]
# for i in range(len(nums)):
# prefix_sum = 0
# for j in range(i, len(nums)):
# prefix_sum += nums[j]
# max_ans = max(max_ans, prefix_sum)
# return max_ans
'''Sol. 2: time O(N) space O(1)'''
cur_sub_arr_sum = max_sum = nums[0]
for num in nums[1:]:
cur_sub_arr_sum += num
if cur_sub_arr_sum < num:
cur_sub_arr_sum = num
max_sum = max(max_sum, cur_sub_arr_sum)
return max_sum