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%E4%BB%8E%E5%A4%B4%E5%AE%9E%E7%8E%B0-logistic%E5%9B%9E%E5%BD%92
Motivation 线性回归用于分类问题存在两个问题 预测结果 \hat{y} 没有限制,可能小于0或大于1,无法解释为概率 平方损失函数不适合分类问题(非凸) Model 符号含义x_i样本i的特征向量(维度为d,特征均为连续数值变量y_i样本i的真实标签(0/1/2/…)p_{j}某样本,经model计算为j类的概率l_i样本i的交叉熵损失 注意区分i,j \begin{align*} \text{for sample } i, , \hat y_j = \vec{\omega}^T_j \vec{x_j} + b \ p_j = \frac{e^{\hat{y}j}}{\sum...
https://chenghui03.github.io/%E4%BB%8E%E5%A4%B4%E5%AE%9E%E7%8E%B0-logistic%E5%9B%9E%E5%BD%92
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