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LogitNormal: incorrect formula in comments #2075

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@yeruouo

The incorrect formula was used in the document and comments.

Logit-normal Log-normal
Normal variable $X \sim \mathcal{N}(\mu, \sigma^2)$ $X \sim \mathcal{N}(\mu, \sigma^2)$
Transformation $Y = \dfrac{1}{1+e^{-X}}$ $Y = e^X$
Inverse transformation $X = \ln\dfrac{Y}{1-Y}$ $X = \ln Y$
Support $(0, 1)$ $(0, +\infty)$
Jacobian $\dfrac{1}{y(1-y)}$ $\dfrac{1}{y}$
PDF $\dfrac{1}{y(1-y)} \cdot \dfrac{1}{\sqrt{2\pi\sigma^2}} \exp\left(-\dfrac{\left(\ln\frac{y}{1-y} - \mu\right)^2}{2\sigma^2}\right)$ $\dfrac{1}{y} \cdot \dfrac{1}{\sqrt{2\pi\sigma^2}} \exp\left(-\dfrac{(\ln y - \mu)^2}{2\sigma^2}\right)$

The correct Logit-normal pdf should be:

$$ f(x; \mu, \sigma) = \dfrac{1}{x(1-x)} \cdot \dfrac{1}{\sqrt{2\pi\sigma^2}} \exp\left(-\dfrac{\left(\text{logit}(x) - \mu\right)^2}{2\sigma^2}\right) $$

Instead of this (written in the comments):

$$ f(x; \mu, \sigma) = \dfrac{1}{x\sqrt{2\pi\sigma^2}} \exp\left(-\dfrac{\left(\text{logit}(x) - \mu\right)^2}{2\sigma^2}\right) $$

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